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## QuestionPhysicsClass 11

Where will a body weigh more, $${2}{k}{m}$$ above the surface of earth or $${2}{k}{m}$$ below the surface of earth ?

At height $${h}{\left(={2}{k}{m}\right)}$$ above the surface of earth.
$${{g}_{{{h}}}=}{g{{\left({1}-\frac{{{2}{h}}}{{{R}}}\right)}}}={g{{\left({1}-\frac{{{2}\times{2}}}{{{R}}}\right)}}}={g{{\left({1}-\frac{{{4}}}{{{R}}}\right)}}}$$
and below the surface of earth at depth
$${d}{\left(={2}{k}{m}\right)}$$
$${{g}_{{{d}}}=}{g{{\left({1}-\frac{{{d}}}{{{R}}}\right)}}}={g{{\left({1}-\frac{{{2}}}{{{R}}}\right)}}}$$
From above, it is clear that
$${{g}_{{{d}}}\gt}{{g}_{{{h}}}}$$ or $${m}{{g}_{{{d}}}\gt}{m}{{g}_{{{h}}}}$$
Hence body well weigh more at a depth $${2}{k}{m}$$ below the surface of earth than $${2}{k}{m}$$ above the surface of earth.