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What volume of \({3}\) molar \({H}{N}{O}_{{{3}}}\) is needed to oxidise \({8}{g}\) of \({F}{e}^{{{3}+}}\), \({H}{N}{O}_{{{3}}}\) gets converted to \({N}{O}\) ?
(A) \({8}{m}{L}\)
(B) \({16}{m}{L}\)
(C) \({32}{m}{L}\)
(D) \({64}{m}{L}\)

Answer

Answer: B
Meq.of \({H}{N}{O}_{{{3}}}=\text{Meq.of}{F}{e}^{{{3}+}}\)
\({\left[\text{Eq.of}{H}{N}{O}_{{{3}}}={M}/{3}\right]}\)
or \({3}\times{3}\times{V}=\frac{{{8}}}{{{56}}}\times{1000}\)
\(\therefore{V}={15.87}{m}{L}\)
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