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## QuestionPhysicsClass 12

What should be the magnitude and direction of electric field?
(A) $$7 Nc^{-1}$$, Vertically up $$\perp$$ to velocity
(B) $$7 Nc^{-1}$$, horizontally and $$\perp$$ to velocity
(C) $$14 Nc^{-1}$$, horizontally parallel to velocity
(D) none of these

$$\vec v\times \vec B=E$$
If angle between B and v is $$\dfrac{\pi}{2}$$
$$v$$ = $$\displaystyle \dfrac{E}{B}$$
or $$vB$$ = $$14(0.5)$$ = $$7 NC^{-1}$$
Thus magnitude of electric field is 7 and direction is horizontal, perpendicular to velocity