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## QuestionMathsClass 7

What per cent is $$250$$ gram of $$4\;kg$$?

We know that $$1\;kg=1000\;g$$
Now, Required fraction $$=\frac {250\;g}{4\;kg}=\frac {250\;g}{4000\;g}=\frac {1}{16}$$
$$\therefore$$ Required per cent $$=(\frac {1}{16}\times 100)\% =6\frac {1}{4}\%$$