Home/Class 8/Maths/

Question and Answer

Question
MathsClass 8

Under the condition that the temperature remains constant, the volume of gas is inversely proportional to its pressure. If the volume of gas is \(630\) cubic centimetres at a pressure of \(360\;mm\) of mercury, then what will be the pressure of the gas if its volume is \(720\) cubic centimetres at the same temperature?

Answer

Since, at constant temperature pressure and volume of a gas are inversely proportional. Let the required pressure be \(p\).
Answer for Under the condition that the temperature remains constant, the volume of gas is inversely proportional to its pressure. If the volume of gas is 630 cubic centimetres at a pressure of 360;mm of mercury, then what will be the pressure of the gas if its volume is 720 cubic centimetres at the same temperature?
Now, \(630\times 360=720\times x\)
\(\Rightarrow\) \(\frac{630\times 360}{720}=x\)
\(x=315\)
So, the required pressure is \(315\;mm\) of mercury.
To Keep Reading This Answer, Download the App
4.6
star pngstar pngstar pngstar pngstar png
Review from Google Play
To Keep Reading This Answer, Download the App
4.6
star pngstar pngstar pngstar pngstar png
Review from Google Play
Correct16
Incorrect0
Still Have Question?
Ask Your QuestionFind More Answer
Watch More Related Solutions
Factorize : \(9x-81\)
Factorize : \(9x-81\)
Math|Class 8
Factorize : \(7a-49b\).
Factorize : \(7a-49b\).
Math|Class 8
Factorize: \(8x^{2}+32x\).
Factorize: \(8x^{2}+32x\).
Math|Class 8
Lemons were bought at\( Rs.\;60\) a dozen and sold at the rate of \(Rs.\;40\) per \(10\). Find the gain or loss per cent.
Lemons were bought at\( Rs.\;60\) a dozen and sold at the rate of \(Rs.\;40\) per \(10\). Find the gain or loss per cent.
Math|Class 8
An asteroid of mass \(m\) is approaching earth, initially at a distance of \(10\ R_e\), with speed \(v_{i}\), it hits the earth with a speed \(v_{f}\)(\(R_{e}\) and \(M_{e}\) are radius and mass of earth), then （ ）
A. \(v^{2}_{f}=v^{2}_{i}+\frac {2Gm}{M_{e}R}(1-\frac {1}{10})\)
B. \(v^{2}_{f}=v^{2}_{i}+\frac {2Gm_{e}}{R_{e}}(1+\frac {1}{10})\)
C. \(v^{2}_{f}=v^{2}_{i}+\frac {2Gm_{e}}{R_{e}}(1-\frac {1}{10})\)
D. \(v^{2}_{f}=v^{2}_{i}+\frac {2Gm}{R_{e}}(1-\frac {1}{10})\)
An asteroid of mass \(m\) is approaching earth, initially at a distance of \(10\ R_e\), with speed \(v_{i}\), it hits the earth with a speed \(v_{f}\)(\(R_{e}\) and \(M_{e}\) are radius and mass of earth), then （ ）
A. \(v^{2}_{f}=v^{2}_{i}+\frac {2Gm}{M_{e}R}(1-\frac {1}{10})\)
B. \(v^{2}_{f}=v^{2}_{i}+\frac {2Gm_{e}}{R_{e}}(1+\frac {1}{10})\)
C. \(v^{2}_{f}=v^{2}_{i}+\frac {2Gm_{e}}{R_{e}}(1-\frac {1}{10})\)
D. \(v^{2}_{f}=v^{2}_{i}+\frac {2Gm}{R_{e}}(1-\frac {1}{10})\)
Physics|Class 12
Factorize: \(25x^{2}y-10xy^{2}\)
Factorize: \(25x^{2}y-10xy^{2}\)
Math|Class 8
If the gravitational force between two objects were proportional to \(\frac1R\) (and not as \(\frac1{R^{2}}\)) where \(R\) is separation between them, then a particle in circular orbit under such a force would have its orbital speed \(v\) proportional to（ ）
A. \(\frac1{R^{2}}\)
B. \(R^0\)
C. \(R^1\)
D. \(\frac1{R}\)
If the gravitational force between two objects were proportional to \(\frac1R\) (and not as \(\frac1{R^{2}}\)) where \(R\) is separation between them, then a particle in circular orbit under such a force would have its orbital speed \(v\) proportional to（ ）
A. \(\frac1{R^{2}}\)
B. \(R^0\)
C. \(R^1\)
D. \(\frac1{R}\)
Physics|Class 12
Factorize: \(x^{3}y^{2}z+x^{2}yz^{2}+xy^{2}z^{2}+x^{3}y^{3}z^{3}\)
Factorize: \(x^{3}y^{2}z+x^{2}yz^{2}+xy^{2}z^{2}+x^{3}y^{3}z^{3}\)
Math|Class 8
Suppose the gravitational force varies inversely as the \(n^{th}\) power of distance. Then the time period of a planet in circular orbit of radius \(R\) around the sun will be proportional to（ ）
A. \(R^{(\frac {n+1}{2})}\)
B. \(R^{(\frac {n-1}{2})}\)
C. \(R^n\)
D. \(R^{(\frac {n-2}{2})}\)
Suppose the gravitational force varies inversely as the \(n^{th}\) power of distance. Then the time period of a planet in circular orbit of radius \(R\) around the sun will be proportional to（ ）
A. \(R^{(\frac {n+1}{2})}\)
B. \(R^{(\frac {n-1}{2})}\)
C. \(R^n\)
D. \(R^{(\frac {n-2}{2})}\)
Physics|Class 12
Factorize \(x^{2}-x-42\) .
Factorize \(x^{2}-x-42\) .
Math|Class 8

Load More

More Solution Recommended For You
NCERT Maths for Class 6
NCERT Physics for Class 6
NCERT Chemistry for Class 6
NCERT Biology for Class 6
NCERT Maths for Class 7
NCERT Physics for Class 7
NCERT Chemistry for Class 7
NCERT Biology for Class 7
NCERT Maths for Class 8
NCERT Physics for Class 8
NCERT Chemistry for Class 8
NCERT Biology for Class 8
Previous
Next