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The storage battery of a car has an emf of \(12 V\). If the internal resistance of the battery is \(0.4 \Omega\), what is the maximum current that can be drawn from the battery?
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The storage battery of a car has an emf of \(12 V\). If the internal resistance of the battery is \(0.4 \Omega\), what is the maximum current that can be drawn from the battery?

Answer

\(30\ A\)
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Solution

Given: emf,\(E=12\;V\)
Internal resistance \(r=0.4 \ \Omega\)
Output voltage,
 \(V=E-Ir\)
 \(r=0.4\; \Omega\)
and for maximum output voltage external resistance, \(R\) will be \(0\).
As per Ohm’s Law,
 \(V=\mathit{IR}\)
 On substituting the given values, we have
\(E=I(R+r)\)
\(I=\frac E{R+r}\)
\(I=\frac{12}{0+0.4}\)
\(I=30A\)
Hence, the maximum current that can be drawn from the battery is\(30\;A\).
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