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# Question and Answer

The smallest division on main scale of a vernier caplliers is $${1}{m}{m}{\quad\text{and}\quad}{10}$$ vernier divisions coincide with $${9}$$ main scale divisions. While measuring the length of a line, the zero mark of the vernier scale lies between $${10.2}{c}{m}{\quad\text{and}\quad}{10.3}{c}{m}$$ and the third division of vernier scale coincides with a main scale division.
(a) Determine the least count of the callopers.
(b) Find the length of the line.
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## QuestionPhysicsClass 11

The smallest division on main scale of a vernier caplliers is $${1}{m}{m}{\quad\text{and}\quad}{10}$$ vernier divisions coincide with $${9}$$ main scale divisions. While measuring the length of a line, the zero mark of the vernier scale lies between $${10.2}{c}{m}{\quad\text{and}\quad}{10.3}{c}{m}$$ and the third division of vernier scale coincides with a main scale division.
(a) Determine the least count of the callopers.
(b) Find the length of the line.

(a) Least Count(LC) $$=\frac{{\text{Smallest division on main scale}}}{{\text{Number of divisions on vernier scale}}}$$
$$=\frac{{{1}}}{{{10}}}{m}{m}={0.1}{m}{m}={0.01}{c}{m}$$
(b) $${L}={N}+{n}{\left({L}{C}\right)}={\left({10.2}+{3}\times{0.01}\right)}{c}{m}={10.23}{c}{m}$$.