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The four quantum numbers of the valence electronof potassium are:
(A) $$4,0,1,+\frac{1}{2}$$
(B) $$4,1,0,+\frac{1}{2}$$
(C) $$4,0,0,+\frac{1}{2}$$
(D) $$4,1,1,+\frac{1}{2}$$
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## QuestionChemistryClass 11

The four quantum numbers of the valence electronof potassium are:
(A) $$4,0,1,+\frac{1}{2}$$
(B) $$4,1,0,+\frac{1}{2}$$
(C) $$4,0,0,+\frac{1}{2}$$
(D) $$4,1,1,+\frac{1}{2}$$

For Potassium, configuration is $$1s^22s^2p^63s^23p^64s^1$$. The outermost electron is thus in 4s orbital unpaired.

The four quantum no. for the valence electron of potassium is

n=4, l=0, m=0 and s= +1/2

Hence, the correct option is C