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# Question and Answer

One mole of $${N}_{{{2}}}{H}_{{{4}}}$$ loses ten moles of electrons to form a new compound $${A}$$. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in $${A}$$? (There is no change in the oxidation state of hydrogen.)
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## QuestionChemistryClass 11

One mole of $${N}_{{{2}}}{H}_{{{4}}}$$ loses ten moles of electrons to form a new compound $${A}$$. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in $${A}$$? (There is no change in the oxidation state of hydrogen.)

## Answer

Answer: 3
$${N}_{{{2}}}{H}_{{{4}}}\rightarrow{\left({X}\right)}+{10}{e}$$
$$\because{X}$$ contains all $${N}$$-atoms
$$\therefore{\left({N}^{{{2}-}}\right)}_{{{2}}}\rightarrow{\left({2}{N}\right)}^{{{a}}}+{10}{e}$$
Therefore $${2}{a}-{\left(-{4}\right)}={10}\Rightarrow{a}=+{3}$$
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