Multiply \(\dfrac{6}{13}\)by the reciprocal of \(\dfrac{-7}{16}\).
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Multiply \(\dfrac{6}{13}\)by the reciprocal of \(\dfrac{-7}{16}\).
Answer
\(\dfrac{-96}{91}\)
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Solution
If we have a number \(a\),then reciprocal of \(a=\frac 1a\)where \(a\neq0\),as reciprocal of \(0\) is not defined
So, reciprocal of\(\dfrac{-7}{16}=\dfrac 1{\dfrac{-7}{16}}=\dfrac{-16}7\)
According to the question,
\(=\dfrac 6{13}\times\dfrac{(-16)}7\)
\(=\dfrac{-96}{91}\)
Hence, the required value is \(\dfrac{-96}{91}\).
So, reciprocal of\(\dfrac{-7}{16}=\dfrac 1{\dfrac{-7}{16}}=\dfrac{-16}7\)
According to the question,
\(=\dfrac 6{13}\times\dfrac{(-16)}7\)
\(=\dfrac{-96}{91}\)
Hence, the required value is \(\dfrac{-96}{91}\).
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