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Is $$\dfrac{8}{9}$$ the multiplicative inverse of $$-1\dfrac{1}{8}$$? Why or why not?
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QuestionClass 8

Is $$\dfrac{8}{9}$$ the multiplicative inverse of $$-1\dfrac{1}{8}$$? Why or why not?

no
4.6
4.6

Solution

Given,$$-1\dfrac{1}{8}$$
$$-1\frac{1}{8}=-1-\frac{1}{8}=\frac{-8-1}{8}=\dfrac{-9}{8}$$
As we know that,
Number $$\times$$ Multiplicative inverse $$=$$1
consider, $$\dfrac{8}{9}\times\dfrac{-9}{8}=-1\neq 1$$
Hence, $$\dfrac{8}{9}$$ is not the multiplicative inverse of $$-1\dfrac{1}{8}$$.