In a square \(ABCD\), the diagonals meet at point O. The \(\Delta AOB\) is （ ）

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In a square \(ABCD\), the diagonals meet at point O. The \(\Delta AOB\) is （ ）

A

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The diagonal of a square bisects each other at \(90^{\circ}\).

\(\therefore AO=BO\).

Hence, \(\Delta AOB\) is a isosceles triangle.

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