If the magnetic field is parallel to the positive \(y\) -axis and the charged particle is moving along the positive \(x\) -axis \((\)Fig.\()\). Which way would the Lorentz force be for a proton \((\) positive charge \()\) ?
Answer
Along \(+z\)-axis.
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Solution
Force, \(\vec F=q(\vec v \times \vec B)\)
According to screw rule or right-hand thumb rule we can say that, the velocity \(\vec v\) of particle is along the \(x\) -axis. While \(\vec B\) the magnetic field is along the \(y\) -axis. So \(\vec v \times \vec B\) is along the \(+z\) -axis. So, for proton the force is along \(+z\)-axis.
According to screw rule or right-hand thumb rule we can say that, the velocity \(\vec v\) of particle is along the \(x\) -axis. While \(\vec B\) the magnetic field is along the \(y\) -axis. So \(\vec v \times \vec B\) is along the \(+z\) -axis. So, for proton the force is along \(+z\)-axis.
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