Home/Class 10/Maths/

Question and Answer

If \( tan\theta =\frac{3}{4},\) evaluate \( \frac{4sin\theta -2cos\theta }{4sin\theta +3cos\theta }\) is
(A) \( 1∕3\)
(B) \( 1∕4\)
(C) \( 1∕5\)
(D) \( 1∕6\)

Answer

(D)
To Keep Reading This Answer, Download the App
4.6
star pngstar pngstar pngstar pngstar png
Review from Google Play
To Keep Reading This Answer, Download the App
4.6
star pngstar pngstar pngstar pngstar png
Review from Google Play

Solution

Here, \( tan\theta =\frac{3}{4}\)
\( A{C}^{2}=16+9\)
\( AC=5\)
\( \therefore  \frac{4sin\theta -2cos\theta }{4sin\theta +3cos\theta } ,     sin\theta =\frac{3}{5},     cos\theta =\frac{4}{5} \)
\( =\frac{4\left(\frac{3}{5}\right)-2\left(\frac{4}{5}\right)}{4\left(\frac{3}{5}\right)+3\left(\frac{4}{5}\right)}= \frac{\frac{12}{5}-\frac{8}{5}}{\frac{12}{5}+\frac{12}{5}}= \frac{12-8}{12+12}= \frac{4}{24}= \frac{1}{6}\)
Solution for If  tantheta =frac{3}{4}, evaluate  frac{4sintheta -2costheta }{4sintheta +3costheta }  is (A)  1∕3(B)  1∕4(C)  1∕5(D)  1∕6
To Keep Reading This Solution, Download the APP
4.6
star pngstar pngstar pngstar pngstar png
Review from Google Play
To Keep Reading This Solution, Download the APP
4.6
star pngstar pngstar pngstar pngstar png
Review from Google Play
Correct47
Incorrect0
Watch More Related Solutions
If A is an acute angle and \( tanA=\frac{5}{12}, \)the value of case A is
(A) \( \frac{11}{5}\)
(B) \( \frac{13}{5}\)
(C) \( \frac{16}{5}\)
(D) \( \frac{17}{5}\)
If \( \alpha \) and \( \beta \) are the roots of the quadratic equation \( 4{x}^{2}+2x-1=0\) then the value of \( \sum _{r=1}^{\infty }\left({\alpha }^{r}+{\beta }^{r}\right)\) is:
(a) \( 2\)
(b) \( 3\)
(c) \( 6\)
(d) \( 0\)
\( \frac{cos\left(90°-\theta \right)cos\theta }{tan\theta }+\frac{co{s}^{2}(90°-\theta )}{1}=\)
(A) 0
(B) 1
(C) 2
(D) 3
\( \frac{sin\theta .cos\theta\;cos(90°-\theta )}{sin(90°-\theta )}+\frac{sin\theta\;cos\theta .sin(90°-\theta )}{cos(90°-\theta )}\) is equal to
(A) 0
(B) 1
(C) 2
(D) 3
\( \frac{sin\theta }{sin(90°-0)}+\frac{cos \theta }{cos(90°-0)}\) is equal to
(A) \( sin\theta .cos\theta \)
(B) \( sec\theta .cosec \theta \)
(C) 1
(D) 2
\( \frac{cos35°}{sin55°}+\frac{tan27°tan63°}{sin30°}-3ta{n}^{2}60°\) is equal to
(A) 6
(B) 6
(C) -6
(D) 3
\( \frac{tan\theta }{cot(90°-\theta )}+\frac{cot\theta }{tan(90°-\theta )}-2cos\theta\;cosec(90°-\theta )\) is equal to
(A) 2
(B) 1
(C) 0
(D) 3
If \( cos\theta =\frac{1}{2}\) , the value of \( \frac{2sec\theta }{1+ta{n}^{2}\theta }\) is
(A) 2
(B) 0
(C) 1
(D) 3
Correct the following statement and rewrite them:
The number of petals and sepals in a flower is always equal.
The value of \( (co{s}^{2}25°+co{s}^{2}65°)\) is
(A) 0
(B) \( si{n}^{2}40°\)
(C) \( co{s}^{2}40°\)
(D) 1

Load More