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## QuestionPhysicsClass 12

If I current is flowing in a potentiometer wire of length $$L$$ and resistance $$R$$, then potential gradient will be

(A) $$\dfrac {IR}{L}$$
(B) $$IRL$$
(C) $$\dfrac {RL}{I}$$
(D) $$\dfrac {IL}{R}$$

The potential is the fall of potential per unit length of potentiometer wire, hence
$$k = \dfrac{V}{L}$$

$$k = \dfrac{IR}{L}$$