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Question and Answer

If A is an acute angle and \( tanA=\frac{5}{12}, \)the value of case A is
(A) \( \frac{11}{5}\)
(B) \( \frac{13}{5}\)
(C) \( \frac{16}{5}\)
(D) \( \frac{17}{5}\)

Answer

(B)
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Solution

Here, \( tanA=\frac{5}{12}\)
\( A{C}^{2}=144+25=169\)
\( AC=13\)
\( \therefore\;cosec\;A=\frac{AC}{BC}=\frac{13}{5}\)
Solution for If A is an acute angle and  tanA=frac{5}{12}, the value of case A is (A)  frac{11}{5}(B)  frac{13}{5}(C)  frac{16}{5}(D)  frac{17}{5}
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