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How many of \({g}\) of \({S}\) are required to produce \({10}\text{moles}\) and \({10}{g}\) of \({H}_{{{2}}}{S}{O}_{{{4}}}\) respectively?

Answer

\(\because{1}\text{mole of}{H}_{{{2}}}{S}{O}_{{{4}}}\text{has}={32}{g}{S}\)
\(\therefore{10}\text{mole of}{H}_{{{2}}}{S}{O}_{{{4}}}\text{has}={32}\times{10}={320}{g}{S}\)
Also \({98}{g}{o}{f}{H}_{{{2}}}{S}{O}_{{{4}}}{h}{a}{s}={32}{g}{S}\)
\(\therefore{10}{g}{o}{f}{H}_{{{2}}}{S}{O}_{{{4}}}{h}{a}{s}={\left({32}\times{10}\right)}/{98}={3.265}{g}{S}\)
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