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## QuestionPhysicsClass 12

Given the mass of iron nucleus as $$55.85u$$ and $$A=56$$, find the nuclear density?

The mass of the iron nucleus is $$m_{\mathit{Fe}}=55.85u$$
The value of $$u$$  is $$9.27\times 10^{-26}\mathit{kg}$$ .
Find the nuclear density as follows:
$$\mathrm{Nuclear}\ \mathrm{density}=\left(\frac{\mathrm{mass}}{\mathrm{volume}}\right)$$
$$\mathrm{Nuclear}\ \mathrm{density}=\left[\frac{9.27\times 10^{-26}}{\frac 4 3\pi \times \left(1.2\times 10^{-15}\right)^3}\right]\times \frac 1{56}$$
$$\mathrm{Nuclear}\ \mathrm{density}=2.29\times 10^{17}\ \mathit{kg}m^{-3}$$
The density of matter in neutron stars is similar to this density. This shows that matter in these objects has been compressed to such an amount that they bear a resemblance to a big nucleus.