Given the mass of iron nucleus as \(55.85u\) and \(A=56\), find the nuclear density?
Answer
The mass of the iron nucleus is \(m_{\mathit{Fe}}=55.85u\)
The value of \(u\) is \(9.27\times 10^{-26}\mathit{kg}\) .
Find the nuclear density as follows:
\(\mathrm{Nuclear}\ \mathrm{density}=\left(\frac{\mathrm{mass}}{\mathrm{volume}}\right)\)
\(\mathrm{Nuclear}\ \mathrm{density}=\left[\frac{9.27\times 10^{-26}}{\frac 4 3\pi \times \left(1.2\times 10^{-15}\right)^3}\right]\times \frac 1{56}\)
\(\mathrm{Nuclear}\ \mathrm{density}=2.29\times 10^{17}\ \mathit{kg}m^{-3}\)
The density of matter in neutron stars is similar to this density. This shows that matter in these objects has been compressed to such an amount that they bear a resemblance to a big nucleus.
The value of \(u\) is \(9.27\times 10^{-26}\mathit{kg}\) .
Find the nuclear density as follows:
\(\mathrm{Nuclear}\ \mathrm{density}=\left(\frac{\mathrm{mass}}{\mathrm{volume}}\right)\)
\(\mathrm{Nuclear}\ \mathrm{density}=\left[\frac{9.27\times 10^{-26}}{\frac 4 3\pi \times \left(1.2\times 10^{-15}\right)^3}\right]\times \frac 1{56}\)
\(\mathrm{Nuclear}\ \mathrm{density}=2.29\times 10^{17}\ \mathit{kg}m^{-3}\)
The density of matter in neutron stars is similar to this density. This shows that matter in these objects has been compressed to such an amount that they bear a resemblance to a big nucleus.
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