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Find the smallest positive value of x and y satisfying $$x – y = \frac{\pi }{4}$$ and $$cot\;x + cot\;y = 2$$
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## QuestionMathsClass 11

Find the smallest positive value of x and y satisfying $$x – y = \frac{\pi }{4}$$ and $$cot\;x + cot\;y = 2$$

$$x=\frac{5\pi }{12}$$ $$y=\frac{\pi }{6}$$
4.6
4.6