Find the position of the image formed by the lens combination given in the figure.
Answer
For \(L_1\) \((\)lens on left\()\)
\(u_1=-30\;\text{cm}\) , \(f_1=10\text{ cm}\)
From lens formula,
\(\frac 1{f_1}=\frac 1{v_1}-\frac 1{u_1}\)
\(\Rightarrow v_1=15\text{ cm}\)
This will act as virtual object for \(L_2\) .
Now for \(L_2\) ,
\(u_2=10\text{ cm}\) \(\{\)distance of image by \(L_1\) from \(L_2\}\)
\(f_2=-10\text{ cm}\)
By using lens formula we get,
\(v_2={\infty}\)
This will act as virtual object for \(L_3\) .
Now for \(L_3\) ,
\(f_3=30\text{ cm}\) , \(u_3={\infty}\)
By using lens formula we get,
\(v_3=30\text{ cm}\)
\({\therefore}\) The position of the image by combination of lens is \(45\text{ cm}\) from \(L_1\) \( [\)on the right\(]\) or \(30\text{ cm}\) from \(L_3\) \([\)on the right\(]\)
\(u_1=-30\;\text{cm}\) , \(f_1=10\text{ cm}\)
From lens formula,
\(\frac 1{f_1}=\frac 1{v_1}-\frac 1{u_1}\)
\(\Rightarrow v_1=15\text{ cm}\)
This will act as virtual object for \(L_2\) .
Now for \(L_2\) ,
\(u_2=10\text{ cm}\) \(\{\)distance of image by \(L_1\) from \(L_2\}\)
\(f_2=-10\text{ cm}\)
By using lens formula we get,
\(v_2={\infty}\)
This will act as virtual object for \(L_3\) .
Now for \(L_3\) ,
\(f_3=30\text{ cm}\) , \(u_3={\infty}\)
By using lens formula we get,
\(v_3=30\text{ cm}\)
\({\therefore}\) The position of the image by combination of lens is \(45\text{ cm}\) from \(L_1\) \( [\)on the right\(]\) or \(30\text{ cm}\) from \(L_3\) \([\)on the right\(]\)
To Keep Reading This Answer, Download the App
4.6
Review from Google Play
To Keep Reading This Answer, Download the App
4.6
Review from Google Play
Correct47
Incorrect0
Still Have Question?
Watch More Related Solutions
A square loop \(PQRS\) carrying a current of \(6.0 A\) is placed near a long wire carrying \(10 A\) as shown in figure. Find the magnetic force on the square loop.
A right-angled triangle abc, made from a metallic wire, moves at a uniform speed v in its plane as shown in figure. A uniform magnetic field B exists in the perpendicular direction. Find the emf induced in the segment ab.
Load More
More Solution Recommended For You