Find the minor of element 6 in the determinant \(\Delta=\left|\begin{array}{lll} {1} & {2} & {3} \\ {4} & {5} & {6} \\ {7} & {8} & {9} \end{array}\right|\)
Find the minor of element 6 in the determinant \(\Delta=\left|\begin{array}{lll} {1} & {2} & {3} \\ {4} & {5} & {6} \\ {7} & {8} & {9} \end{array}\right|\)
Answer
Since 6 lies in the second row and third column, its minor M23 is given by \(\mathrm{M}_{23}=\left|\begin{array}{ll} {1} & {2} \\ {7} & {8} \end{array}\right|\) = 8 – 14 = – 6 (obtained by deleting R2 and C3 in \(\Delta\))
If a, b, c, are in A.P, then the determinant \(\left|\begin{array}{ccc} {x+2} & {x+3} & {x+2 a} \\ {x+3} & {x+4} & {x+2 b} \\ {x+4} & {x+5} & {x+2 c} \end{array}\right|\) is