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Find the minor of element 6 in the determinant $$\Delta=\left|\begin{array}{lll} {1} & {2} & {3} \\ {4} & {5} & {6} \\ {7} & {8} & {9} \end{array}\right|$$
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## QuestionMathsClass 12

Find the minor of element 6 in the determinant $$\Delta=\left|\begin{array}{lll} {1} & {2} & {3} \\ {4} & {5} & {6} \\ {7} & {8} & {9} \end{array}\right|$$

Since 6 lies in the second row and third column, its minor M23 is given by
$$\mathrm{M}_{23}=\left|\begin{array}{ll} {1} & {2} \\ {7} & {8} \end{array}\right|$$ = 8 – 14 = – 6 (obtained by deleting R2 and C3 in $$\Delta$$)