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Question

Find the Roots of\( x ^ { 2 } +20x-2020 \).

Answer

\( x=\frac { -b±\sqrt[] { b ^ { 2 } -4ac } } { 2a } \)
\( a=1,\,\,b=20,\,c=-2020 \)
\( x=\frac { -20±\sqrt[] { (20) ^ { 2 } -4×1×(-2020) } } { 2×1 } \\ ⇒x=\frac { -20±\sqrt[] { 8480 } } { 2 } \\ ⇒x=\frac { -20±4\sqrt[] { 530 } } { 2 } \\ ⇒x=\frac { -20 } { 2 }±\frac { 4\sqrt[] { 530 } } { 2 } \\ ⇒x=-10±2\sqrt[] { 530 } \)
Hence roots are \( -10+2\sqrt[] { 530 } \) and\( -10-2\sqrt[] { 530 } \).
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