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Find the LCM and HCF of $$26$$and $$91$$ and verify that LCM $$\times$$ HCF $$=$$Product of two numbers
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## QuestionMathsClass 10

Find the LCM and HCF of $$26$$and $$91$$ and verify that LCM $$\times$$ HCF $$=$$Product of two numbers

4.6
4.6

## Solution

Solution:
Doing prime factorization of $$26$$ and $$91$$.

$$26=2\times 13$$ and $$91=7\times 13$$
$$\therefore$$ LCM of $$26$$ and $$91$$ $$=2\times 7\times 13=182$$
and HCF of $$26$$ and $$91 =13$$
Now,
LCM $$\times$$HCF$$=182\times 13=2366$$
Product of two numbers$$=26\times 91=2366$$
Since,$$182\times 13=26\times 91$$
so,  LCM $$\times$$ HCF $$=$$Product of two numbers
Hence proved.