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Find the LCM and HCF of \(26 \)and \(91\) and verify that LCM \(\times\) HCF \(=\)Product of two numbers
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Find the LCM and HCF of \(26 \)and \(91\) and verify that LCM \(\times\) HCF \(=\)Product of two numbers

Answer

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Solution

Solution:
Doing prime factorization of \(26\) and \(91\).
Solution for Find the LCM and HCF of 26 and 91 and verify that LCM times HCF =Product of two numbers
\(26=2\times 13\) and \(91=7\times 13\)
\(\therefore \) LCM of \(26\) and \(91\) \(=2\times 7\times 13=182\)
and HCF of \(26\) and \(91 =13 \)
Now,
LCM \(\times \)HCF\(=182\times 13=2366\) 
Product of two numbers\(=26\times 91=2366\)
Since,\(182\times 13=26\times 91\)
so,  LCM \(\times\) HCF \(=\)Product of two numbers
Hence proved.
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