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Question

Find H.C.F. of \(81x^{3}y^{3}\) and \(21xy\).

Answer

Using prime factorisation, we have,
\(81x^3y^3=3\times3\times3\times3\times x\times x\times x\times y\times y\times y\)
\(21xy=3\times 7\times x\times y\)
H.C.F of \(81x^{3}y^{3}\) and \(21xy\) is \(3\times x\times y=3xy\)
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