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Digital signals
\((i)\) do not provide a continuous set of values,
\((\mathit{ii})\) represent values as discrete steps,
\((\mathit{iii})\) can utilize binary system, and
\((\mathit{iv})\) can utilize decimal as well as binary systems.
Which of the above statements are true?
\(\left(a\right)\left(i\right)\) & \(\left(\mathit{iii}\right)\) only
\(\left(b\right)\left(\mathit{ii}\right)\) & \(\left(\mathit{iii}\right)\) only
\(\left(c\right)\left(i\right),\left(\mathit{ii}\right)\) & \(\left(\mathit{iii}\right)\) but not \((\mathit{iv})\)
\((d)\) all of \(\left(i\right),\left(\mathit{ii}\right),\left(\mathit{iii}\right)\) & \((\mathit{iv})\)


\(\left(c\right)\left(i\right),\left(\mathit{ii}\right)\) & \(\left(\mathit{iii}\right)\) but not \((\mathit{iv})\)
Digital signals use only two steps in general-\((\)High & Low\()\)
\((i)\) signal is not using continuous set of values
\((\mathit{ii})\) only two steps \(0\) & \(1\)  \((\)discrete\()\) are there
\((\mathit{iii})\) Binary system \((\)uses only \(0\) & \(1\)\()\)
\((\mathit{iv})\) There are only two steps \((\)decimal system can not be used\()\)
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