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Calculate the percentage increase in length of a wire of diameter 1 mm stretched by a force of half kilo gram weight. Young's modulus of elasticity of wire is \({12}\times{10}^{{{11}}}{\left.{d}{y}\right.}{n}{e}/{c}{m}^{{{2}}}\)


Here, diameter of wire.
Force applied , \({F}=\frac{{1}}{{2}}{k}{g}{w}{t}\)
\(\therefore\%\) increase in length =\(\frac{{\Delta{l}}}{{{l}}}\times{100}=\frac{{{4}{F}\times{100}}}{{\pi{D}^{{{2}}}{Y}}}\)
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