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A wire of radius $$1 mm$$ is bent in the form of a circle of radius $$10 cm$$. The bending moment will be $$(Y =2\times10^{11}N/m^{2})$$

(A) 3.14 N/m
(B) 6.28 N/m
(C) 1.57 N/m
(D) 15.7 N/m
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## QuestionPhysicsClass 11

A wire of radius $$1 mm$$ is bent in the form of a circle of radius $$10 cm$$. The bending moment will be $$(Y =2\times10^{11}N/m^{2})$$

(A) 3.14 N/m
(B) 6.28 N/m
(C) 1.57 N/m
(D) 15.7 N/m

Bending Moment $$C=\dfrac { Y{ I }_{ G } }{ R }$$
where $$Y= 2\times { 10 }^{ 11 }N/{m}^{2}$$
$$R= 10cm= 0.1m$$
$${ I }_{ G }=\dfrac{\pi{R}^{4}}{4} = \dfrac{\pi{0.1}^{4}}{4} =7.85\times{10}^{-5} m^{4}$$
Put these in the expression for $$C$$,
$$C=1.57N/m$$