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## QuestionPhysicsClass 11

At what temperature is the Fahrenheit scale reading equal to twice of Celsius ?
(A) $$40^0C$$
(B) $$160^0C$$
(C) $$80^0C$$
(D) $$100^0C$$

We know the relation between Fahrenheit scale and degree celsius,

$$\dfrac{C-0}{100}=\dfrac{F-32}{180}$$

Given,

$$F=2C$$

Then,

$$\dfrac{C}{100}=\dfrac{2C-32}{180}$$

$$\dfrac{C}{100}=\dfrac{C-16}{90}$$

$$\implies 9C=10C-160$$

$$\implies C=160^0C$$