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## QuestionPhysicsClass 12

A resistor of $$200\;\Omega$$  and capacitance $$\text{15}\; \mu F$$  are connected in series to a $${220\;\text{V}}$$  and $${50\;\text{Hz}}$$ source. Calculate current in the circuit.

According to the question $$R=200\;\Omega$$ and $$C=15\; \mu F, V=220\;V$$ and $$\text{frequency}=50\;\text{Hz}$$
The impedance of the circuit= $$Z=\sqrt{R^2+X_c^2}=\sqrt{R^2+\left(2\mathit{\pi vC}\right)^2}$$
$$\sqrt{200^2+\left(2\times 3.14\times 50\times 15\times 10^{-6}\right)^2}$$
$$=291.67\;\Omega$$
$$I=\frac V Z$$
$$=\frac{220}{291.67}=0.755\;A$$