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## QuestionPhysicsClass 12

A pure inductor of $$25\;\mathit{mH}$$ is connected to a source of $$220\;V$$ . Find the inductive reactance and the rms current in circuit if the frequency of the source is $$50\;\mathit{Hz}$$ .

$$X=7.85\ \Omega$$
$$I=28\ A$$
4.6
4.6

## Solution

The inductive reactance that is the resistance offered by the inductor
$$X=\omega L$$
$$X=2\pi {\nu}\times L$$
According to the question,
$$V=220\;V$$
$$L=25\;\mathit{mH}=0.025H$$
Frequency, $$\nu=50\;\mathit{Hz}$$
Inductive reactance,
$$X=2\times 3.14\times 50\times 0.025=7.85\;\Omega$$
$$V=IR$$ for resistor and
$$V=IX$$ for inductor
Current,
$$I=\frac{V}{X}$$
$$I= \frac{220}{7.85}=28\;A$$
4.6
4.6
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