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Question and Answer

A pure inductor of \(25\;\mathit{mH}\) is connected to a source of \(220\;V\) . Find the inductive reactance and the rms current in circuit if the frequency of the source is \(50\;\mathit{Hz}\) .

Answer

\(X=7.85\ \Omega\)
\(I=28\ A\)
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Solution

The inductive reactance that is the resistance offered by the inductor
\(X=\omega L\)
 \(X=2\pi {\nu}\times L\)
According to the question,
\(V=220\;V\) 
\(L=25\;\mathit{mH}=0.025H\)
Frequency, \(\nu=50\;\mathit{Hz}\)
Inductive reactance,
\(X=2\times 3.14\times 50\times 0.025=7.85\;\Omega\)
\(V=IR\) for resistor and
\(V=IX\) for inductor
Current,
\(I=\frac{V}{X}\)
\(I= \frac{220}{7.85}=28\;A\) 
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