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A pole 6 m high casts a shadow 2$$\sqrt 3$$m long on the ground, then the sun’s elevation is
• $$45^\circ$$
• $$60^\circ$$
• $$75^\circ$$
• $$30^\circ$$
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## QuestionClass 10

A pole 6 m high casts a shadow 2$$\sqrt 3$$m long on the ground, then the sun’s elevation is
• $$45^\circ$$
• $$60^\circ$$
• $$75^\circ$$
• $$30^\circ$$

Let height = 6m
length of shadow = $$2 \sqrt{3 m}$$
$$\theta$$ is angle of elevation
tan$$\theta$$ = (height) / (shadow length)
$$= \frac{6}{2}\sqrt 3 = \sqrt 3$$
$$\theta = \frac{\pi }{3}$$
Angle of inclination is = 60o
Therefore the choice is: B