A gas mixture consists of \(2\:mol\) of oxygen and \(4\:mol\) of argon at temperature \(T\). Neglecting all vibrational modes, the total internal energy of the system is

(A) \(4RT\)

(B) \(15RT\)

(C) \(9RT\)

(D) \(11RT\)

(A) \(4RT\)

(B) \(15RT\)

(C) \(9RT\)

(D) \(11RT\)

Answer: D

\(O_2\) molecule has 3 translational and 2 rotational degrees i.e total of 5 degrees of freedom.

Since Argon is a noble gas, it consists only of atoms and the energy is purely translational kinetic energy.

Total internal energy: \(U = 2 \times \dfrac{5}{2}RT + 4 \times \dfrac{3}{2}RT = 11RT\)

\(O_2\) molecule has 3 translational and 2 rotational degrees i.e total of 5 degrees of freedom.

Since Argon is a noble gas, it consists only of atoms and the energy is purely translational kinetic energy.

Total internal energy: \(U = 2 \times \dfrac{5}{2}RT + 4 \times \dfrac{3}{2}RT = 11RT\)

To Keep Reading This Answer, Download the App

4.6

Review from Google Play

To Keep Reading This Answer, Download the App

4.6

Review from Google Play

Correct4

Incorrect0

Still Have Question?

Load More

More Solution Recommended For You