A car covers a distance in \(40\) minutes with an average speed of \(60\ km\) per hour. The average speed to cover the same distance in \(30\) minutes is （ ）

Speed

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A car covers a distance in \(40\) minutes with an average speed of \(60\ km\) per hour. The average speed to cover the same distance in \(30\) minutes is （ ）

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Given: Time = \(40\) minutes = \(\frac{40}{60}=\frac23\) hour, Speed =\(60\ km\) per hour.

We know that, \(\text{Speed}=\frac{\text{Distance}}{\text{Time}}\).

\(\therefore\) Distance covered by a car = \(\text{Speed}\times\text{Time}\)\(=60\ \frac{km}{h}\times\frac{40}{60}\ h\) [\(\because 1\ h=60\) minutes]

\(=40\ km\).

Now, the average speed to cover the same distance in \(30\) minutes is,

\(\text{Speed}=\frac{\text{Distance}}{\text{Time}}\)

\(\Rightarrow \text{Speed}=\frac{40\ km}{\frac{30}{60}\ h}\)

\(=\frac{60\times40}{30}\ \frac{km}{h}\)

\(=2\times40\ \frac{km}{h}\)

\(=80\ \frac{km}{h}\)

Hence, the average speed to cover the same distance in \(30\) minutes is \(80\ \frac{km}{h}\).

We know that, \(\text{Speed}=\frac{\text{Distance}}{\text{Time}}\).

\(\therefore\) Distance covered by a car = \(\text{Speed}\times\text{Time}\)\(=60\ \frac{km}{h}\times\frac{40}{60}\ h\) [\(\because 1\ h=60\) minutes]

\(=40\ km\).

Now, the average speed to cover the same distance in \(30\) minutes is,

\(\text{Speed}=\frac{\text{Distance}}{\text{Time}}\)

\(\Rightarrow \text{Speed}=\frac{40\ km}{\frac{30}{60}\ h}\)

\(=\frac{60\times40}{30}\ \frac{km}{h}\)

\(=2\times40\ \frac{km}{h}\)

\(=80\ \frac{km}{h}\)

Hence, the average speed to cover the same distance in \(30\) minutes is \(80\ \frac{km}{h}\).

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