Here, we are given emf \((E)\) as \(10V,\) Resistance \((r)\) as \(3\Omega \) and current \(I\) is \(0.5A.\)
Let the unknown resistance be \(R\Omega \) .
Using Ohm's law,
Hence, the resistance of the resistor will be \(17\Omega \) .
To verify the voltage of the battery,
Hence the voltage of the battery is \(8.5\text V\) .