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## QuestionMaths

$$5x ^ {2} -6x-2 = 0$$

As we know that a quadratic equation of the form $$a{x}^{2}+bx+c=0$$ the solution $$($$zeroes$$)$$ of the quadratic equation is given by
$$x=\frac{-b\pm \sqrt{{b}^{2}-4ac}}{2a}$$
$$a=5$$
$$b=-6$$
$$c=-2$$
Therefore, using the formula
$$x=\frac{-(-6)\pm \sqrt{{\left(-6\right)}^{2}-4\left(5\right)(-2)}}{2\times\;5}=\frac{6\pm \sqrt{36+40}}{10}$$
$$x=\frac{6\pm \sqrt{76}}{10}$$
$$x=\frac{6+\sqrt{76}}{10}$$ and $$\frac{6-\sqrt{76}}{10}$$
Hence, the solutions of the given quadratic equation are $$\left(\frac{6+\sqrt{76}}{10},\frac{6-\sqrt{76}}{10}\right)$$
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